In this paper, we prove a Hardy-type inequality for fuzzy integrals. More precisely, we show thatfenced({cauchy integral}01 fp (x) d x)frac(1, p + 1) ≥ {cauchy integral}01 fenced(frac(F, x))p d x,where p ≥ 1, f : [0, 1] → [0, ∞) is an integrable function and F (x) = {cauchy integral}0x f (t) d t. An analogous inequality is also obtained on the interval [0, ∞). © 2008 Elsevier Inc. All rights reserved.